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[leetcode]71. Simplify Path简化路径
阅读量:5235 次
发布时间:2019-06-14

本文共 1647 字,大约阅读时间需要 5 分钟。

Given an absolute path for a file (Unix-style), simplify it. Or in other words, convert it to the canonical path.

In a UNIX-style file system, a period . refers to the current directory. Furthermore, a double period .. moves the directory up a level. For more information, see: 

Note that the returned canonical path must always begin with a slash /, and there must be only a single slash / between two directory names. The last directory name (if it exists) must not end with a trailing /. Also, the canonical path must be the shorteststring representing the absolute path.

Example 1:

Input: "/home/"Output: "/home"Explanation: Note that there is no trailing slash after the last directory name.

Example 2:

Input: "/../"Output: "/"Explanation: Going one level up from the root directory is a no-op, as the root level is the highest level you can go.

Example 3:

Input: "/home//foo/"Output: "/home/foo"Explanation: In the canonical path, multiple consecutive slashes are replaced by a single one.

Example 4:

Input: "/a/./b/../../c/"Output: "/c"

 

 

题意

遇到"."的情况直接去掉,遇到".."删掉它上面挨着的一个路径, 求简化后的路径

 

思路

很接近real industry的题目

将input通过/分离出来, 利用Stack来模拟遇到"."和".."的情况

 

代码

1 class Solution { 2     public String simplifyPath(String path) { 3         String[] arr = path.split("/"); 4         StringBuilder sb = new StringBuilder(); 5         Stack
stack = new Stack<>(); 6 7 for (int i = 0; i
result String 20 while (!stack.isEmpty()) {21 sb.insert(0, "/" + stack.pop());22 } 23 return sb.toString(); 24 }25 }

 

转载于:https://www.cnblogs.com/liuliu5151/p/10953072.html

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